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../../protocols/http2.rst:155
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The information exchanged over an HTTP/2.0 session is composed of frames. A frame starts with a 9 bytes-long header that carries several types of information. The HTTP/2.0 frames have a variable length. The `Length` field of the header contains the length of the frame payload in bytes. As this field is encoded as a 24 bits field, an HTTP/2.0 frame cannot be longer than :math:`2^{24} -1` bytes. It should be noted that :rfc:`7540` assumes a maximum size of :math:`2^{14}` bytes, i.e. 16,384 bytes for the HTTP/2.0 frame payload unless a longer maximum frame length has been negotiated at the beginning of the session using the HTTP/2.0 `Settings` frame that will be described later. The next field of the frames header indicates the frame type. The first frame types are `Data` which contains data from web objects and `Headers` containing HTTP/2.0 headers. When a client retrieves a web object from a server, it always receives an HTTP/2.0 `Headers` frame followed by an HTTP/2.0 `Data` frame. The `Headers` frame information contains essentially the same HTTP headers as the ones supported by HTTP/1.1, but those are encoded by leveraging a data compression technique that minimizes the number of bytes required to transmit them.
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../../protocols/ipv6.rst:105
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IPv6 addressing architecture
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../../protocols/ethernet.rst:59
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The last field of the Ethernet frame is a 32 bit Cyclical Redundancy Check (CRC). This CRC is able to catch a much larger number of transmission errors than the Internet checksum used by IP, UDP and TCP [SGP98]_. The format of the Ethernet frame is shown below.
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../../protocols/routing.rst:75
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Internal router : A router whose directly connected networks belong to the area
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../../protocols/rpc.rst:100
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The second sub-problem is how to reach the callee. A simple solution to this problem is to make sure that the callee listens on a specific port on the remote machine and then exchange information with this server process. This is the solution chosen for JSON-RPC [JSON-RPC2]_. JSON-RPC can be used over the connectionless or the connection-oriented transport service. A JSON-RPC request contains the following fields:
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../../protocols/ssh.rst:204
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a key used by the client (resp. server) to encrypt the data that it sends
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../../protocols/tcp.rst:50
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the `RST` is used in case of problems or when an invalid segment has been received
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../../protocols/tls.rst:47
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990
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../../protocols/transport-service.rst:65
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The second transport service is the connection-oriented service. On the Internet, this service is often called the `byte-stream service` as it creates a reliable byte stream between the two applications that are linked by a transport connection. Like the datagram service, the networked applications that use the byte-stream service are identified by the host on which they run and a port number. These hosts can be identified by an address or a name. The figure below illustrates two applications that are using the byte-stream service provided by the TCP protocol on IPv6 hosts. The byte stream service provided by TCP is reliable and bidirectional.
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../../protocols/udp.rst:74
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the entire UDP segment, including its header
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../../protocols/wifi.rst:24
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11 Mbps
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../../bibliography.rst:74
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Feldmeier, D. C., `Fast software implementation of error detection codes <https://dx.doi.org/10.1109/90.477710>`_. IEEE/ACM Transactions Networking 3, 6 (Dec. 1995), 640-651.
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../../glossary.rst:24
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broadcast
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../../exercises/ex-sharing.rst:559
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How is the maximum round-trip-time influenced if the buffers of router `R1` store 10 packets ?
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../../principles/sharing.rst:133
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Besides the link bandwidth, the buffers on the network nodes are the second type of resource that needs to be shared inside the network. The node buffers play an important role in the operation of the network because that can be used to absorb transient traffic peaks. Consider again the example above. Assume that on average host `A` and host `B` send a group of three packets every ten seconds. Their combined transmission rate (0.6 packets per second) is, on average, lower than the network capacity (1 packet per second). However, if they both start to transmit at the same time, node `R1` will have to absorb a burst of packets. This burst of packets is a small `network congestion`. We will say that a network is congested, when the sum of the traffic demand from the hosts is larger than the network capacity :math:`\sum{demand}>capacity`. This `network congestion` problem is one of the most difficult resource sharing problem in computer networks. `Congestion` occurs in almost all networks. Minimizing the amount of congestion is a key objective for many network operators. In most cases, they will have to accept transient congestion, i.e. congestion lasting a few seconds or perhaps minutes, but will want to prevent congestion that lasts days or months. For this, they can rely on a wide range of solutions. We briefly present some of these in the paragraphs below.
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../../principles/security.rst:310
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A secret key encryption scheme is a perfectly reversible functions, i.e. given an encryption function `E`, there is an associated decryption function `D` such that :math:`\forall k \forall M : D(K, E(M,K))=M`.
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../../exercises/dns.rst:73
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A DNS implementation such as `dig`, and more importantly a name resolver such as bind_ or unbound_, always checks that the received DNS reply contains the same identifier as the DNS request that it sent. Why is this so important ?
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../../exercises/ipv6.rst:220
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Assuming that the following IPv6 addresses are used :
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../../exercises/lan.rst:250
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The state of switch ``s9`` is different. The output of :manpage:`brctl(8)` indicates that the root identifier is ``0003.f63545ab5f79`` which is at a distance of ``1`` from switch ``s9``. The root port on ``s9`` is port `1`, i.e. ``s9-eth1``. Two of the ports of this switch forward data packets, the root port and the ``s9-eth3`` which is a designated port. The ``s9-eth2`` port is a blocked port.
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../../exercises/routing-policies.rst:197
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``Code==0``
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